Base | Representation |
---|---|
bin | 10001100111000101100… |
… | …010101011010011110011 |
3 | 11021200201220211102000101 |
4 | 101213011202223103303 |
5 | 124311442200341034 |
6 | 2323542550133231 |
7 | 153301612242265 |
oct | 21470542532363 |
9 | 4250656742011 |
10 | 1210200012019 |
11 | 4272743a2099 |
12 | 176665651217 |
13 | 8a176864a8b |
14 | 42807073b35 |
15 | 21730406514 |
hex | 119c58ab4f3 |
1210200012019 has 2 divisors, whose sum is σ = 1210200012020. Its totient is φ = 1210200012018.
The previous prime is 1210200012011. The next prime is 1210200012079. The reversal of 1210200012019 is 9102100020121.
It is a happy number.
It is a weak prime.
It is an emirp because it is prime and its reverse (9102100020121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1210200012019 - 23 = 1210200012011 is a prime.
It is a super-2 number, since 2×12102000120192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1210200011987 and 1210200012005.
It is not a weakly prime, because it can be changed into another prime (1210200012011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605100006009 + 605100006010.
It is an arithmetic number, because the mean of its divisors is an integer number (605100006010).
Almost surely, 21210200012019 is an apocalyptic number.
1210200012019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1210200012019 is an equidigital number, since it uses as much as digits as its factorization.
1210200012019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 19.
The spelling of 1210200012019 in words is "one trillion, two hundred ten billion, two hundred million, twelve thousand, nineteen".
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