Base | Representation |
---|---|
bin | 1011000000011011100000… |
… | …0100010011110001011111 |
3 | 1120211221101221210100100022 |
4 | 2300012320010103301133 |
5 | 3041234404304311033 |
6 | 41423330452022355 |
7 | 2356225054210235 |
oct | 260067004236137 |
9 | 46757357710308 |
10 | 12102011010143 |
11 | 394648579765a |
12 | 143554b0019bb |
13 | 69a2a3a2cc52 |
14 | 2dba51b62955 |
15 | 15ec03995098 |
hex | b01b8113c5f |
12102011010143 has 2 divisors, whose sum is σ = 12102011010144. Its totient is φ = 12102011010142.
The previous prime is 12102011010101. The next prime is 12102011010169. The reversal of 12102011010143 is 34101011020121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12102011010143 - 218 = 12102010747999 is a prime.
It is a super-3 number, since 3×121020110101433 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12102011010343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051005505071 + 6051005505072.
It is an arithmetic number, because the mean of its divisors is an integer number (6051005505072).
Almost surely, 212102011010143 is an apocalyptic number.
12102011010143 is a deficient number, since it is larger than the sum of its proper divisors (1).
12102011010143 is an equidigital number, since it uses as much as digits as its factorization.
12102011010143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 12102011010143 its reverse (34101011020121), we get a palindrome (46203022030264).
The spelling of 12102011010143 in words is "twelve trillion, one hundred two billion, eleven million, ten thousand, one hundred forty-three".
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