12102034121 has 2 divisors, whose sum is σ = 12102034122. Its totient is φ = 12102034120.

The previous prime is 12102034099. The next prime is 12102034141. The reversal of 12102034121 is 12143020121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10307325625 + 1794708496 = 101525^2 + 42364^2 .

It is a cyclic number.

It is not a de Polignac number, because 12102034121 - 2¹⁴ = 12102017737 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 12102034121.

It is not a weakly prime, because it can be changed into another prime (12102034141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051017060 + 6051017061.

It is an arithmetic number, because the mean of its divisors is an integer number (6051017061).

Almost surely, 2^12102034121 is an apocalyptic number.

It is an amenable number.

12102034121 is a deficient number, since it is larger than the sum of its proper divisors (1).

12102034121 is an equidigital number, since it uses as much as digits as its factorization.

12102034121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 12102034121 its reverse (12143020121), we get a palindrome (24245054242).

The spelling of 12102034121 in words is "twelve billion, one hundred two million, thirty-four thousand, one hundred twenty-one".