Base | Representation |
---|---|
bin | 1011000000011011101010… |
… | …1110001100010100010011 |
3 | 1120211221112001120220102111 |
4 | 2300012322232030110103 |
5 | 3041240002204402313 |
6 | 41423335122330151 |
7 | 2356226134560631 |
oct | 260067256142423 |
9 | 46757461526374 |
10 | 12102055544083 |
11 | 39464a894466a |
12 | 1435561ab9957 |
13 | 69a2b00233ab |
14 | 2dba57a36351 |
15 | 15ec0784043d |
hex | b01bab8c513 |
12102055544083 has 8 divisors (see below), whose sum is σ = 12114804630656. Its totient is φ = 12089307542400.
The previous prime is 12102055544021. The next prime is 12102055544093. The reversal of 12102055544083 is 38044555020121.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12102055544083 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12102055544003) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23109835 + ... + 23627707.
It is an arithmetic number, because the mean of its divisors is an integer number (1514350578832).
Almost surely, 212102055544083 is an apocalyptic number.
12102055544083 is a deficient number, since it is larger than the sum of its proper divisors (12749086573).
12102055544083 is an equidigital number, since it uses as much as digits as its factorization.
12102055544083 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 542445.
The product of its (nonzero) digits is 192000, while the sum is 40.
The spelling of 12102055544083 in words is "twelve trillion, one hundred two billion, fifty-five million, five hundred forty-four thousand, eighty-three".
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