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1210212103130 = 25179676096147
BaseRepresentation
bin10001100111000110010…
…000110011001111011010
311021200202202120200220022
4101213012100303033122
5124312003244300010
62323544101230442
7153302120101322
oct21470620631732
94250682520808
101210212103130
11427280200348
12176669702422
138a179209394
1442808900282
15217314e3d55
hex119c64333da

1210212103130 has 16 divisors (see below), whose sum is σ = 2190551519520. Its totient is φ = 481380455952.

The previous prime is 1210212103091. The next prime is 1210212103147. The reversal of 1210212103130 is 313012120121.

It is a super-2 number, since 2×12102121031302 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1210212103099 and 1210212103108.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 338046284 + ... + 338049863.

It is an arithmetic number, because the mean of its divisors is an integer number (136909469970).

Almost surely, 21210212103130 is an apocalyptic number.

1210212103130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1210212103130 is a deficient number, since it is larger than the sum of its proper divisors (980339416390).

1210212103130 is a wasteful number, since it uses less digits than its factorization.

1210212103130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 676096333.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1210212103130 its reverse (313012120121), we get a palindrome (1523224223251).

The spelling of 1210212103130 in words is "one trillion, two hundred ten billion, two hundred twelve million, one hundred three thousand, one hundred thirty".

Divisors: 1 2 5 10 179 358 895 1790 676096147 1352192294 3380480735 6760961470 121021210313 242042420626 605106051565 1210212103130