Base | Representation |
---|---|
bin | 1110011011010… |
… | …10001111111001 |
3 | 22102201112012022 |
4 | 13031222033321 |
5 | 221440141213 |
6 | 20001524225 |
7 | 2666444111 |
oct | 715521771 |
9 | 272645168 |
10 | 121021433 |
11 | 6234a215 |
12 | 34643675 |
13 | 1c0c3b20 |
14 | 12104041 |
15 | a958308 |
hex | 736a3f9 |
121021433 has 4 divisors (see below), whose sum is σ = 130330788. Its totient is φ = 111712080.
The previous prime is 121021429. The next prime is 121021447. The reversal of 121021433 is 334120121.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 334120121 = 137 ⋅2438833.
It can be written as a sum of positive squares in 2 ways, for example, as 53173264 + 67848169 = 7292^2 + 8237^2 .
It is a cyclic number.
It is not a de Polignac number, because 121021433 - 22 = 121021429 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (121021403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4654658 + ... + 4654683.
It is an arithmetic number, because the mean of its divisors is an integer number (32582697).
Almost surely, 2121021433 is an apocalyptic number.
121021433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
121021433 is a deficient number, since it is larger than the sum of its proper divisors (9309355).
121021433 is an equidigital number, since it uses as much as digits as its factorization.
121021433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9309354.
The product of its (nonzero) digits is 144, while the sum is 17.
The square root of 121021433 is about 11000.9741841348. The cubic root of 121021433 is about 494.6379463176.
Adding to 121021433 its reverse (334120121), we get a palindrome (455141554).
The spelling of 121021433 in words is "one hundred twenty-one million, twenty-one thousand, four hundred thirty-three".
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