Base | Representation |
---|---|
bin | 1011000000011100010010… |
… | …1001100011101010010111 |
3 | 1120211221221122222212202111 |
4 | 2300013010221203222113 |
5 | 3041240322324214033 |
6 | 41423403432251451 |
7 | 2356233226360006 |
oct | 260070451435227 |
9 | 46757848885674 |
10 | 12102222101143 |
11 | 3946583965429 |
12 | 14355a9840b87 |
13 | 69a30869b575 |
14 | 2dba71bd0c3d |
15 | 15ec172907cd |
hex | b01c4a63a97 |
12102222101143 has 2 divisors, whose sum is σ = 12102222101144. Its totient is φ = 12102222101142.
The previous prime is 12102222101141. The next prime is 12102222101147. The reversal of 12102222101143 is 34110122220121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12102222101143 - 21 = 12102222101141 is a prime.
Together with 12102222101141, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12102222101141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051111050571 + 6051111050572.
It is an arithmetic number, because the mean of its divisors is an integer number (6051111050572).
Almost surely, 212102222101143 is an apocalyptic number.
12102222101143 is a deficient number, since it is larger than the sum of its proper divisors (1).
12102222101143 is an equidigital number, since it uses as much as digits as its factorization.
12102222101143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 12102222101143 its reverse (34110122220121), we get a palindrome (46212344321264).
The spelling of 12102222101143 in words is "twelve trillion, one hundred two billion, two hundred twenty-two million, one hundred one thousand, one hundred forty-three".
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