Base | Representation |
---|---|
bin | 1011000000011100010010… |
… | …1101110100110110100110 |
3 | 1120211221221202002201201121 |
4 | 2300013010231310312212 |
5 | 3041240323121021014 |
6 | 41423403512244154 |
7 | 2356233242030245 |
oct | 260070455646646 |
9 | 46757852081647 |
10 | 12102223220134 |
11 | 394658455a113 |
12 | 14355aa0a065a |
13 | 69a3089a09a8 |
14 | 2dba7200295c |
15 | 15ec17412124 |
hex | b01c4b74da6 |
12102223220134 has 4 divisors (see below), whose sum is σ = 18153334830204. Its totient is φ = 6051111610066.
The previous prime is 12102223220119. The next prime is 12102223220167. The reversal of 12102223220134 is 43102232220121.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 12102223220099 and 12102223220108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3025555805032 + ... + 3025555805035.
It is an arithmetic number, because the mean of its divisors is an integer number (4538333707551).
Almost surely, 212102223220134 is an apocalyptic number.
12102223220134 is a deficient number, since it is larger than the sum of its proper divisors (6051111610070).
12102223220134 is an equidigital number, since it uses as much as digits as its factorization.
12102223220134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6051111610069.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 12102223220134 its reverse (43102232220121), we get a palindrome (55204455440255).
The spelling of 12102223220134 in words is "twelve trillion, one hundred two billion, two hundred twenty-three million, two hundred twenty thousand, one hundred thirty-four".
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