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1210223113 = 11110020283
BaseRepresentation
bin100100000100010…
…1000101000001001
310010100020201000021
41020020220220021
54434304114423
6320031140441
741663504161
oct11010505011
93110221007
101210223113
115711595a0
12299374721
13163963768
14b6a315a1
15713a995d
hex48228a09

1210223113 has 4 divisors (see below), whose sum is σ = 1320243408. Its totient is φ = 1100202820.

The previous prime is 1210223011. The next prime is 1210223129. The reversal of 1210223113 is 3113220121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1210223113 - 217 = 1210092041 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1210223153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55010131 + ... + 55010152.

It is an arithmetic number, because the mean of its divisors is an integer number (330060852).

Almost surely, 21210223113 is an apocalyptic number.

It is an amenable number.

1210223113 is a deficient number, since it is larger than the sum of its proper divisors (110020295).

1210223113 is a wasteful number, since it uses less digits than its factorization.

1210223113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110020294.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1210223113 is about 34788.2611379183. The cubic root of 1210223113 is about 1065.6677285298.

Adding to 1210223113 its reverse (3113220121), we get a palindrome (4323443234).

The spelling of 1210223113 in words is "one billion, two hundred ten million, two hundred twenty-three thousand, one hundred thirteen".

Divisors: 1 11 110020283 1210223113