1210232100113 has 4 divisors (see below), whose sum is σ = 1211033049408. Its totient is φ = 1209431150820.

The previous prime is 1210232100067. The next prime is 1210232100139. The reversal of 1210232100113 is 3110012320121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1210232100113 is a prime.

It is a super-2 number, since 2×1210232100113² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1210232100091 and 1210232100100.

It is not an unprimeable number, because it can be changed into a prime (1210232100713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 400472381 + ... + 400475402.

It is an arithmetic number, because the mean of its divisors is an integer number (302758262352).

Almost surely, 2^{1210232100113} is an apocalyptic number.

It is an amenable number.

1210232100113 is a deficient number, since it is larger than the sum of its proper divisors (800949295).

1210232100113 is an equidigital number, since it uses as much as digits as its factorization.

1210232100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 800949294.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1210232100113 its reverse (3110012320121), we get a palindrome (4320244420234).

The spelling of 1210232100113 in words is "one trillion, two hundred ten billion, two hundred thirty-two million, one hundred thousand, one hundred thirteen".