Base | Representation |
---|---|
bin | 10110100010110010… |
… | …10110111001101111 |
3 | 1011020110222010102022 |
4 | 23101121112321233 |
5 | 144241333121033 |
6 | 5320545420355 |
7 | 605631655004 |
oct | 132131267157 |
9 | 34213863368 |
10 | 12103020143 |
11 | 5150926195 |
12 | 241933a6bb |
13 | 11ab5c4ba6 |
14 | 82b5978ab |
15 | 4ac820098 |
hex | 2d1656e6f |
12103020143 has 2 divisors, whose sum is σ = 12103020144. Its totient is φ = 12103020142.
The previous prime is 12103020131. The next prime is 12103020169. The reversal of 12103020143 is 34102030121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12103020143 - 210 = 12103019119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12103020343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051510071 + 6051510072.
It is an arithmetic number, because the mean of its divisors is an integer number (6051510072).
Almost surely, 212103020143 is an apocalyptic number.
12103020143 is a deficient number, since it is larger than the sum of its proper divisors (1).
12103020143 is an equidigital number, since it uses as much as digits as its factorization.
12103020143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 12103020143 its reverse (34102030121), we get a palindrome (46205050264).
The spelling of 12103020143 in words is "twelve billion, one hundred three million, twenty thousand, one hundred forty-three".
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