Base | Representation |
---|---|
bin | 1011000000011111010011… |
… | …1100001110011011110101 |
3 | 1120212001001010112022102202 |
4 | 2300013310330032123311 |
5 | 3041244002232120201 |
6 | 41424020053514245 |
7 | 2356262265065414 |
oct | 260076474163365 |
9 | 46761033468382 |
10 | 12103032301301 |
11 | 394695a232837 |
12 | 1435795042985 |
13 | 69a4074b3146 |
14 | 2dbb0b65347b |
15 | 15ec6347ec6b |
hex | b01f4f0e6f5 |
12103032301301 has 2 divisors, whose sum is σ = 12103032301302. Its totient is φ = 12103032301300.
The previous prime is 12103032301291. The next prime is 12103032301319. The reversal of 12103032301301 is 10310323030121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10699342870225 + 1403689431076 = 3270985^2 + 1184774^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12103032301301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12103032301331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051516150650 + 6051516150651.
It is an arithmetic number, because the mean of its divisors is an integer number (6051516150651).
Almost surely, 212103032301301 is an apocalyptic number.
It is an amenable number.
12103032301301 is a deficient number, since it is larger than the sum of its proper divisors (1).
12103032301301 is an equidigital number, since it uses as much as digits as its factorization.
12103032301301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 12103032301301 its reverse (10310323030121), we get a palindrome (22413355331422).
The spelling of 12103032301301 in words is "twelve trillion, one hundred three billion, thirty-two million, three hundred one thousand, three hundred one".
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