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12103112000000 = 29567216127
BaseRepresentation
bin1011000000011111100110…
…1100010000001000000000
31120212001020200111102111102
42300013321230100020000
53041244133133000000
641424032022033532
72356264253365220
oct260077154201000
946761220442442
1012103112000000
1139469a021862a
1214357b78788a8
1369a41ab69338
142dbb1807c080
1515ec6a4743d5
hexb01f9b10200

12103112000000 has 280 divisors, whose sum is σ = 34546267802112. Its totient is φ = 4149619200000.

The previous prime is 12103111999967. The next prime is 12103112000011. The reversal of 12103112000000 is 21130121.

It is a tau number, because it is divible by the number of its divisors (280).

It is an unprimeable number.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 55891937 + ... + 56108063.

Almost surely, 212103112000000 is an apocalyptic number.

12103112000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12103112000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17273133901056).

12103112000000 is an abundant number, since it is smaller than the sum of its proper divisors (22443155802112).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12103112000000 is an frugal number, since it uses more digits than its factorization.

12103112000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 216182 (or 216141 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 12103112000000 its reverse (21130121), we get a palindrome (12103133130121).

The spelling of 12103112000000 in words is "twelve trillion, one hundred three billion, one hundred twelve million", and thus it is an aban number.