Base | Representation |
---|---|
bin | 111000010111000011… |
… | …0010110001110010101 |
3 | 102120101222000001101112 |
4 | 1300232012112032111 |
5 | 3440333310000432 |
6 | 131333534304405 |
7 | 11513204163554 |
oct | 1605606261625 |
9 | 376358001345 |
10 | 121032500117 |
11 | 47369766801 |
12 | 1b559658105 |
13 | b54b093499 |
14 | 5c02513d9b |
15 | 32359567b2 |
hex | 1c2e196395 |
121032500117 has 2 divisors, whose sum is σ = 121032500118. Its totient is φ = 121032500116.
The previous prime is 121032500041. The next prime is 121032500143. The reversal of 121032500117 is 711005230121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113888700676 + 7143799441 = 337474^2 + 84521^2 .
It is an emirp because it is prime and its reverse (711005230121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 121032500117 - 216 = 121032434581 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 121032500092 and 121032500101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121032500177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60516250058 + 60516250059.
It is an arithmetic number, because the mean of its divisors is an integer number (60516250059).
Almost surely, 2121032500117 is an apocalyptic number.
It is an amenable number.
121032500117 is a deficient number, since it is larger than the sum of its proper divisors (1).
121032500117 is an equidigital number, since it uses as much as digits as its factorization.
121032500117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 420, while the sum is 23.
Adding to 121032500117 its reverse (711005230121), we get a palindrome (832037730238).
The spelling of 121032500117 in words is "one hundred twenty-one billion, thirty-two million, five hundred thousand, one hundred seventeen".
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