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1210341000131 = 47179571434089
BaseRepresentation
bin10001100111001101111…
…100100000001111000011
311021201002202010100100022
4101213031330200033003
5124312234244001011
62324004544044055
7153305243516324
oct21471574401703
94251082110308
101210341000131
11427336a3959a
121766a490362b
138a199b29ab3
144281ba9444b
152173c9a58db
hex119cdf203c3

1210341000131 has 8 divisors (see below), whose sum is σ = 1236162634560. Its totient is φ = 1184522269888.

The previous prime is 1210341000109. The next prime is 1210341000161. The reversal of 1210341000131 is 1310001430121.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1210341000131 - 222 = 1210336805827 is a prime.

It is a super-2 number, since 2×12103410001312 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1210341000161) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 126935 + ... + 1561023.

It is an arithmetic number, because the mean of its divisors is an integer number (154520329320).

Almost surely, 21210341000131 is an apocalyptic number.

1210341000131 is a deficient number, since it is larger than the sum of its proper divisors (25821634429).

1210341000131 is a wasteful number, since it uses less digits than its factorization.

1210341000131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1452093.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1210341000131 its reverse (1310001430121), we get a palindrome (2520342430252).

The spelling of 1210341000131 in words is "one trillion, two hundred ten billion, three hundred forty-one million, one hundred thirty-one", and thus it is an aban number.

Divisors: 1 47 17957 843979 1434089 67402183 25751936173 1210341000131