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12103854763933 is a prime number
BaseRepresentation
bin1011000000100010010111…
…1101101010111110011101
31120212010011110010202001201
42300020211331222332131
53041302143304421213
641424233434035501
72356321542645562
oct260104575527635
946763143122051
1012103854763933
113947241516119
121435984578b91
1369a5089cc31a
142dbb88988869
1515ecb07926dd
hexb0225f6af9d

12103854763933 has 2 divisors, whose sum is σ = 12103854763934. Its totient is φ = 12103854763932.

The previous prime is 12103854763879. The next prime is 12103854763943. The reversal of 12103854763933 is 33936745830121.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10470026290564 + 1633828473369 = 3235742^2 + 1278213^2 .

It is a cyclic number.

It is not a de Polignac number, because 12103854763933 - 217 = 12103854632861 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12103854763943) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6051927381966 + 6051927381967.

It is an arithmetic number, because the mean of its divisors is an integer number (6051927381967).

It is a 1-persistent number, because it is pandigital, but 2⋅12103854763933 = 24207709527866 is not.

Almost surely, 212103854763933 is an apocalyptic number.

It is an amenable number.

12103854763933 is a deficient number, since it is larger than the sum of its proper divisors (1).

12103854763933 is an equidigital number, since it uses as much as digits as its factorization.

12103854763933 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9797760, while the sum is 55.

The spelling of 12103854763933 in words is "twelve trillion, one hundred three billion, eight hundred fifty-four million, seven hundred sixty-three thousand, nine hundred thirty-three".