121040133 has 4 divisors (see below), whose sum is σ = 161386848. Its totient is φ = 80693420.

The previous prime is 121040131. The next prime is 121040137. The reversal of 121040133 is 331040121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 331040121 = 3 ⋅110346707.

It is a cyclic number.

It is not a de Polignac number, because 121040133 - 2¹ = 121040131 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121040131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20173353 + ... + 20173358.

It is an arithmetic number, because the mean of its divisors is an integer number (40346712).

Almost surely, 2^121040133 is an apocalyptic number.

It is an amenable number.

121040133 is a deficient number, since it is larger than the sum of its proper divisors (40346715).

121040133 is an equidigital number, since it uses as much as digits as its factorization.

121040133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40346714.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 121040133 is about 11001.8240760339. The cubic root of 121040133 is about 494.6634218415.

Adding to 121040133 its reverse (331040121), we get a palindrome (452080254).

The spelling of 121040133 in words is "one hundred twenty-one million, forty thousand, one hundred thirty-three".