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12104516152117 is a prime number
BaseRepresentation
bin1011000000100100110101…
…1000101010101100110101
31120212011212112122202002101
42300021031120222230311
53041310022113331432
641424423221542101
72356344123443164
oct260111530525465
946764775582071
1012104516152117
113947550892924
121435b29b74931
1369a5b2a3c98c
142dbc0c7513db
1515eced8894e7
hexb024d62ab35

12104516152117 has 2 divisors, whose sum is σ = 12104516152118. Its totient is φ = 12104516152116.

The previous prime is 12104516152109. The next prime is 12104516152189. The reversal of 12104516152117 is 71125161540121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8770565172196 + 3333950979921 = 2961514^2 + 1825911^2 .

It is a cyclic number.

It is not a de Polignac number, because 12104516152117 - 23 = 12104516152109 is a prime.

It is a super-2 number, since 2×121045161521172 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12104516153117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6052258076058 + 6052258076059.

It is an arithmetic number, because the mean of its divisors is an integer number (6052258076059).

Almost surely, 212104516152117 is an apocalyptic number.

It is an amenable number.

12104516152117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12104516152117 is an equidigital number, since it uses as much as digits as its factorization.

12104516152117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16800, while the sum is 37.

Adding to 12104516152117 its reverse (71125161540121), we get a palindrome (83229677692238).

The spelling of 12104516152117 in words is "twelve trillion, one hundred four billion, five hundred sixteen million, one hundred fifty-two thousand, one hundred seventeen".