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12104516153117 is a prime number
BaseRepresentation
bin1011000000100100110101…
…1000101010111100011101
31120212011212112122210110102
42300021031120222330131
53041310022113344432
641424423221550445
72356344123446123
oct260111530527435
946764775583412
1012104516153117
113947550893653
121435b29b75425
1369a5b2a4027b
142dbc0c751913
1515eced889962
hexb024d62af1d

12104516153117 has 2 divisors, whose sum is σ = 12104516153118. Its totient is φ = 12104516153116.

The previous prime is 12104516153101. The next prime is 12104516153153. The reversal of 12104516153117 is 71135161540121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6609120614041 + 5495395539076 = 2570821^2 + 2344226^2 .

It is a cyclic number.

It is not a de Polignac number, because 12104516153117 - 24 = 12104516153101 is a prime.

It is a super-2 number, since 2×121045161531172 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12104516152117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6052258076558 + 6052258076559.

It is an arithmetic number, because the mean of its divisors is an integer number (6052258076559).

Almost surely, 212104516153117 is an apocalyptic number.

It is an amenable number.

12104516153117 is a deficient number, since it is larger than the sum of its proper divisors (1).

12104516153117 is an equidigital number, since it uses as much as digits as its factorization.

12104516153117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25200, while the sum is 38.

Adding to 12104516153117 its reverse (71135161540121), we get a palindrome (83239677693238).

The spelling of 12104516153117 in words is "twelve trillion, one hundred four billion, five hundred sixteen million, one hundred fifty-three thousand, one hundred seventeen".