Base | Representation |
---|---|
bin | 10110100011000001… |
… | …11111001011010000 |
3 | 1011020121201201212020 |
4 | 23101200333023100 |
5 | 144242341120422 |
6 | 5321100331440 |
7 | 605654654553 |
oct | 132140771320 |
9 | 34217651766 |
10 | 12105020112 |
11 | 5151a71859 |
12 | 2419b43b80 |
13 | 11abb452c3 |
14 | 82b95869a |
15 | 4acab795c |
hex | 2d183f2d0 |
12105020112 has 40 divisors (see below), whose sum is σ = 31291032960. Its totient is φ = 4032460800.
The previous prime is 12105020069. The next prime is 12105020143. The reversal of 12105020112 is 21102050121.
It is a junction number, because it is equal to n+sod(n) for n = 12105020091 and 12105020100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1912 + ... + 155607.
It is an arithmetic number, because the mean of its divisors is an integer number (782275824).
Almost surely, 212105020112 is an apocalyptic number.
12105020112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
12105020112 is an abundant number, since it is smaller than the sum of its proper divisors (19186012848).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12105020112 is a wasteful number, since it uses less digits than its factorization.
12105020112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 159131 (or 159125 counting only the distinct ones).
The product of its (nonzero) digits is 40, while the sum is 15.
Adding to 12105020112 its reverse (21102050121), we get a palindrome (33207070233).
The spelling of 12105020112 in words is "twelve billion, one hundred five million, twenty thousand, one hundred twelve".
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