121100220031 has 4 divisors (see below), whose sum is σ = 138400251472. Its totient is φ = 103800188592.

The previous prime is 121100219963. The next prime is 121100220071. The reversal of 121100220031 is 130022001121.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 130022001121 = 38287 ⋅3395983.

It is a cyclic number.

It is not a de Polignac number, because 121100220031 - 2¹⁷ = 121100088959 is a prime.

It is a super-2 number, since 2×121100220031² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121100219993 and 121100220020.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121100220071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8650015710 + ... + 8650015723.

It is an arithmetic number, because the mean of its divisors is an integer number (34600062868).

Almost surely, 2^121100220031 is an apocalyptic number.

121100220031 is a deficient number, since it is larger than the sum of its proper divisors (17300031441).

121100220031 is an equidigital number, since it uses as much as digits as its factorization.

121100220031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17300031440.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 121100220031 its reverse (130022001121), we get a palindrome (251122221152).

The spelling of 121100220031 in words is "one hundred twenty-one billion, one hundred million, two hundred twenty thousand, thirty-one".