Base | Representation |
---|---|
bin | 10001100111110101010… |
… | …111001010111000111101 |
3 | 11021202210211110221222121 |
4 | 101213311113022320331 |
5 | 124320113042131023 |
6 | 2324154330042541 |
7 | 153330523504210 |
oct | 21476527127075 |
9 | 4252724427877 |
10 | 1211002302013 |
11 | 427646257479 |
12 | 17684a279451 |
13 | 8a273b3a09a |
14 | 42881837777 |
15 | 2177aa81d5d |
hex | 119f55cae3d |
1211002302013 has 4 divisors (see below), whose sum is σ = 1384002630880. Its totient is φ = 1038001973148.
The previous prime is 1211002302011. The next prime is 1211002302043. The reversal of 1211002302013 is 3102032001121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1211002302013 - 21 = 1211002302011 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1211002302011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86500164423 + ... + 86500164436.
It is an arithmetic number, because the mean of its divisors is an integer number (346000657720).
Almost surely, 21211002302013 is an apocalyptic number.
It is an amenable number.
1211002302013 is a deficient number, since it is larger than the sum of its proper divisors (173000328867).
1211002302013 is an equidigital number, since it uses as much as digits as its factorization.
1211002302013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 173000328866.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 1211002302013 its reverse (3102032001121), we get a palindrome (4313034303134).
The spelling of 1211002302013 in words is "one trillion, two hundred eleven billion, two million, three hundred two thousand, thirteen".
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