121100313301 has 4 divisors (see below), whose sum is σ = 132109432704. Its totient is φ = 110091193900.

The previous prime is 121100313293. The next prime is 121100313329. The reversal of 121100313301 is 103313001121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 103313001121 = 11 ⋅9392091011.

It is a cyclic number.

It is not a de Polignac number, because 121100313301 - 2³ = 121100313293 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121100313371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5504559685 + ... + 5504559706.

It is an arithmetic number, because the mean of its divisors is an integer number (33027358176).

Almost surely, 2^121100313301 is an apocalyptic number.

121100313301 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

121100313301 is a deficient number, since it is larger than the sum of its proper divisors (11009119403).

121100313301 is a wasteful number, since it uses less digits than its factorization.

121100313301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11009119402.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 121100313301 its reverse (103313001121), we get a palindrome (224413314422).

The spelling of 121100313301 in words is "one hundred twenty-one billion, one hundred million, three hundred thirteen thousand, three hundred one".