Search a number
-
+
121101434131 = 312233878597
BaseRepresentation
bin111000011001000110…
…1010011110100010011
3102120120202201021002011
41300302031103310103
53441003431343011
6131344440003351
711515002130426
oct1606215236423
9376522637064
10121101434131
11473a4669967
121b578760557
13b55c44aa42
145c0b7399bd
15323ba21621
hex1c32353d13

121101434131 has 4 divisors (see below), whose sum is σ = 121105343952. Its totient is φ = 121097524312.

The previous prime is 121101434087. The next prime is 121101434171. The reversal of 121101434131 is 131434101121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 121101434131 - 223 = 121093045523 is a prime.

It is a super-2 number, since 2×1211014341312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (121101434171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1908076 + ... + 1970521.

It is an arithmetic number, because the mean of its divisors is an integer number (30276335988).

Almost surely, 2121101434131 is an apocalyptic number.

121101434131 is a deficient number, since it is larger than the sum of its proper divisors (3909821).

121101434131 is an equidigital number, since it uses as much as digits as its factorization.

121101434131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3909820.

The product of its (nonzero) digits is 288, while the sum is 22.

Adding to 121101434131 its reverse (131434101121), we get a palindrome (252535535252).

The spelling of 121101434131 in words is "one hundred twenty-one billion, one hundred one million, four hundred thirty-four thousand, one hundred thirty-one".

Divisors: 1 31223 3878597 121101434131