121101434132 has 24 divisors (see below), whose sum is σ = 246173410560. Its totient is φ = 51049784160.

The previous prime is 121101434087. The next prime is 121101434171. The reversal of 121101434132 is 231434101121.

It is a junction number, because it is equal to n+sod(n) for n = 121101434098 and 121101434107.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 35449532 + ... + 35452947.

It is an arithmetic number, because the mean of its divisors is an integer number (10257225440).

Almost surely, 2^121101434132 is an apocalyptic number.

It is an amenable number.

121101434132 is an abundant number, since it is smaller than the sum of its proper divisors (125071976428).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121101434132 is a wasteful number, since it uses less digits than its factorization.

121101434132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 70902551 (or 70902549 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 121101434132 its reverse (231434101121), we get a palindrome (352535535253).

The spelling of 121101434132 in words is "one hundred twenty-one billion, one hundred one million, four hundred thirty-four thousand, one hundred thirty-two".