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1211021220023 is a prime number
BaseRepresentation
bin10001100111110110011…
…111010101100010110111
311021202212011002002121122
4101213312133111202313
5124320132413020043
62324200243334155
7153331143345566
oct21476637254267
94252764062548
101211021220023
114276559a889a
1217685468135b
138a277a31b84
144288415dbdd
152177c56c368
hex119f67d58b7

1211021220023 has 2 divisors, whose sum is σ = 1211021220024. Its totient is φ = 1211021220022.

The previous prime is 1211021219999. The next prime is 1211021220163. The reversal of 1211021220023 is 3200221201121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1211021220023 - 28 = 1211021219767 is a prime.

It is a super-2 number, since 2×12110212200232 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1211021219983 and 1211021220010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211021220323) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605510610011 + 605510610012.

It is an arithmetic number, because the mean of its divisors is an integer number (605510610012).

Almost surely, 21211021220023 is an apocalyptic number.

1211021220023 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211021220023 is an equidigital number, since it uses as much as digits as its factorization.

1211021220023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 1211021220023 its reverse (3200221201121), we get a palindrome (4411242421144).

The spelling of 1211021220023 in words is "one trillion, two hundred eleven billion, twenty-one million, two hundred twenty thousand, twenty-three".