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1211101000133 is a prime number
BaseRepresentation
bin10001100111111011001…
…111101011000111000101
311021210001201012100100112
4101213323033223013011
5124320313324001013
62324212213322405
7153333132434633
oct21477317530705
94253051170315
101211101000133
11427696a39872
12176877336405
138a28b41613b
14428909aa353
152178457aba8
hex119fb3eb1c5

1211101000133 has 2 divisors, whose sum is σ = 1211101000134. Its totient is φ = 1211101000132.

The previous prime is 1211101000093. The next prime is 1211101000139. The reversal of 1211101000133 is 3310001011121.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 993406903204 + 217694096929 = 996698^2 + 466577^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211101000133 - 28 = 1211100999877 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211101000139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605550500066 + 605550500067.

It is an arithmetic number, because the mean of its divisors is an integer number (605550500067).

Almost surely, 21211101000133 is an apocalyptic number.

It is an amenable number.

1211101000133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211101000133 is an equidigital number, since it uses as much as digits as its factorization.

1211101000133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 1211101000133 its reverse (3310001011121), we get a palindrome (4521102011254).

The spelling of 1211101000133 in words is "one trillion, two hundred eleven billion, one hundred one million, one hundred thirty-three", and thus it is an aban number.