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1211101099997 is a prime number
BaseRepresentation
bin10001100111111011010…
…000000011011111011101
311021210001201101102100012
4101213323100003133131
5124320313340144442
62324212215413005
7153333133332035
oct21477320033735
94253051342305
101211101099997
11427696aa78a8
12176877384165
138a28b44c729
14428909d48c5
152178459a582
hex119fb4037dd

1211101099997 has 2 divisors, whose sum is σ = 1211101099998. Its totient is φ = 1211101099996.

The previous prime is 1211101099951. The next prime is 1211101100029. The reversal of 1211101099997 is 7999901011121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1207688904601 + 3412195396 = 1098949^2 + 58414^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211101099997 - 210 = 1211101098973 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211101099597) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605550549998 + 605550549999.

It is an arithmetic number, because the mean of its divisors is an integer number (605550549999).

Almost surely, 21211101099997 is an apocalyptic number.

It is an amenable number.

1211101099997 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211101099997 is an equidigital number, since it uses as much as digits as its factorization.

1211101099997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 91854, while the sum is 50.

The spelling of 1211101099997 in words is "one trillion, two hundred eleven billion, one hundred one million, ninety-nine thousand, nine hundred ninety-seven".