Base | Representation |
---|---|
bin | 11011100010011000100101… |
… | …101111111000011000110010 |
3 | 120212211000101120112001000202 |
4 | 123202120211233320120302 |
5 | 111333232012001340310 |
6 | 1105325115505115202 |
7 | 34336626463055105 |
oct | 3342304557703062 |
9 | 525730346461022 |
10 | 121110121121330 |
11 | 35653572047490 |
12 | 116bbb52628b02 |
13 | 527683501c823 |
14 | 21c9a927c873c |
15 | e0054393c3a5 |
hex | 6e2625bf8632 |
121110121121330 has 16 divisors (see below), whose sum is σ = 237816237838464. Its totient is φ = 44040044044080.
The previous prime is 121110121121287. The next prime is 121110121121347. The reversal of 121110121121330 is 33121121011121.
It is a super-3 number, since 3×1211101211213303 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 550500550442 + ... + 550500550661.
It is an arithmetic number, because the mean of its divisors is an integer number (14863514864904).
Almost surely, 2121110121121330 is an apocalyptic number.
121110121121330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
121110121121330 is a deficient number, since it is larger than the sum of its proper divisors (116706116717134).
121110121121330 is a wasteful number, since it uses less digits than its factorization.
121110121121330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1101001101121.
The product of its (nonzero) digits is 72, while the sum is 20.
Adding to 121110121121330 its reverse (33121121011121), we get a palindrome (154231242132451).
The spelling of 121110121121330 in words is "one hundred twenty-one trillion, one hundred ten billion, one hundred twenty-one million, one hundred twenty-one thousand, three hundred thirty".
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