Base | Representation |
---|---|
bin | 1011000000111101000010… |
… | …0101001010010110010111 |
3 | 1120212210122021010200100102 |
4 | 2300033100211022112113 |
5 | 3041411323111210241 |
6 | 41431415555004315 |
7 | 2356664113146515 |
oct | 260172045122627 |
9 | 46783567120312 |
10 | 12111012210071 |
11 | 394a284728365 |
12 | 143724159969b |
13 | 69b0a9810458 |
14 | 2dc2673ab4b5 |
15 | 16007dd0c39b |
hex | b03d094a597 |
12111012210071 has 2 divisors, whose sum is σ = 12111012210072. Its totient is φ = 12111012210070.
The previous prime is 12111012210047. The next prime is 12111012210083. The reversal of 12111012210071 is 17001221011121.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (17001221011121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12111012210071 - 218 = 12111011947927 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12111012290071) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055506105035 + 6055506105036.
It is an arithmetic number, because the mean of its divisors is an integer number (6055506105036).
Almost surely, 212111012210071 is an apocalyptic number.
12111012210071 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111012210071 is an equidigital number, since it uses as much as digits as its factorization.
12111012210071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 12111012210071 its reverse (17001221011121), we get a palindrome (29112233221192).
The spelling of 12111012210071 in words is "twelve trillion, one hundred eleven billion, twelve million, two hundred ten thousand, seventy-one".
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