Base | Representation |
---|---|
bin | 1011000000111101000100… |
… | …1010100011001011110010 |
3 | 1120212210122221120121212022 |
4 | 2300033101022203023302 |
5 | 3041411333113323442 |
6 | 41431420545031442 |
7 | 2356664262360146 |
oct | 260172112431362 |
9 | 46783587517768 |
10 | 12111022011122 |
11 | 394a28a212001 |
12 | 1437244925582 |
13 | 69b0ab8625a8 |
14 | 2dc2687dd226 |
15 | 16007eae63d2 |
hex | b03d12a32f2 |
12111022011122 has 4 divisors (see below), whose sum is σ = 18166533016686. Its totient is φ = 6055511005560.
The previous prime is 12111022011097. The next prime is 12111022011191. The reversal of 12111022011122 is 22111022011121.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12111019447921 + 2563201 = 3480089^2 + 1601^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 12111022011122.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3027755502779 + ... + 3027755502782.
Almost surely, 212111022011122 is an apocalyptic number.
12111022011122 is a deficient number, since it is larger than the sum of its proper divisors (6055511005564).
12111022011122 is an equidigital number, since it uses as much as digits as its factorization.
12111022011122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6055511005563.
The product of its (nonzero) digits is 32, while the sum is 17.
Adding to 12111022011122 its reverse (22111022011121), we get a palindrome (34222044022243).
Subtracting 12111022011122 from its reverse (22111022011121), we obtain a palindrome (9999999999999).
The spelling of 12111022011122 in words is "twelve trillion, one hundred eleven billion, twenty-two million, eleven thousand, one hundred twenty-two".
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