1211121130231 has 2 divisors, whose sum is σ = 1211121130232. Its totient is φ = 1211121130230.

The previous prime is 1211121130223. The next prime is 1211121130237. The reversal of 1211121130231 is 1320311211121.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1211121130231 - 2³ = 1211121130223 is a prime.

It is a super-2 number, since 2×1211121130231² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1211121130199 and 1211121130208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211121130237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605560565115 + 605560565116.

It is an arithmetic number, because the mean of its divisors is an integer number (605560565116).

Almost surely, 2^{1211121130231} is an apocalyptic number.

1211121130231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211121130231 is an equidigital number, since it uses as much as digits as its factorization.

1211121130231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 1211121130231 its reverse (1320311211121), we get a palindrome (2531432341352).

The spelling of 1211121130231 in words is "one trillion, two hundred eleven billion, one hundred twenty-one million, one hundred thirty thousand, two hundred thirty-one".