Base | Representation |
---|---|
bin | 1011000000111101110001… |
… | …1111110000111111110111 |
3 | 1120212211011012022021002202 |
4 | 2300033130133300333313 |
5 | 3041412230300401403 |
6 | 41431451455455115 |
7 | 2360002061316443 |
oct | 260173437607767 |
9 | 46784135267082 |
10 | 12111212122103 |
11 | 394a377560216 |
12 | 143729852749b |
13 | 69b10c0666b3 |
14 | 2dc285b69823 |
15 | 16009164a688 |
hex | b03dc7f0ff7 |
12111212122103 has 2 divisors, whose sum is σ = 12111212122104. Its totient is φ = 12111212122102.
The previous prime is 12111212122099. The next prime is 12111212122111. The reversal of 12111212122103 is 30122121211121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12111212122103 - 22 = 12111212122099 is a prime.
It is a super-2 number, since 2×121112121221032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12111212122153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055606061051 + 6055606061052.
It is an arithmetic number, because the mean of its divisors is an integer number (6055606061052).
Almost surely, 212111212122103 is an apocalyptic number.
12111212122103 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111212122103 is an equidigital number, since it uses as much as digits as its factorization.
12111212122103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 20.
Adding to 12111212122103 its reverse (30122121211121), we get a palindrome (42233333333224).
The spelling of 12111212122103 in words is "twelve trillion, one hundred eleven billion, two hundred twelve million, one hundred twenty-two thousand, one hundred three".
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