1211121421333 has 4 divisors (see below), whose sum is σ = 1282363857900. Its totient is φ = 1139878984768.

The previous prime is 1211121421309. The next prime is 1211121421339. The reversal of 1211121421333 is 3331241211121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 989989180324 + 221132241009 = 994982^2 + 470247^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211121421333 - 2¹³ = 1211121413141 is a prime.

It is a super-2 number, since 2×1211121421333² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1211121421298 and 1211121421307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1211121421339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35621218258 + ... + 35621218291.

It is an arithmetic number, because the mean of its divisors is an integer number (320590964475).

Almost surely, 2^{1211121421333} is an apocalyptic number.

It is an amenable number.

1211121421333 is a deficient number, since it is larger than the sum of its proper divisors (71242436567).

1211121421333 is an equidigital number, since it uses as much as digits as its factorization.

1211121421333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71242436566.

The product of its digits is 864, while the sum is 25.

Adding to 1211121421333 its reverse (3331241211121), we get a palindrome (4542362632454).

The spelling of 1211121421333 in words is "one trillion, two hundred eleven billion, one hundred twenty-one million, four hundred twenty-one thousand, three hundred thirty-three".