Base | Representation |
---|---|
bin | 111000011001011011… |
… | …0011111110110011011 |
3 | 102120121112000211001011 |
4 | 1300302312133312123 |
5 | 3441014212400243 |
6 | 131345503234351 |
7 | 11515162660216 |
oct | 1606266376633 |
9 | 376545024034 |
10 | 121112231323 |
11 | 473aa773a66 |
12 | 1b5802a89b7 |
13 | b56175b405 |
14 | 5c0cd4a77d |
15 | 323c95589d |
hex | 1c32d9fd9b |
121112231323 has 2 divisors, whose sum is σ = 121112231324. Its totient is φ = 121112231322.
The previous prime is 121112231321. The next prime is 121112231327. The reversal of 121112231323 is 323132211121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121112231323 - 21 = 121112231321 is a prime.
Together with 121112231321, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 121112231294 and 121112231303.
It is not a weakly prime, because it can be changed into another prime (121112231321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60556115661 + 60556115662.
It is an arithmetic number, because the mean of its divisors is an integer number (60556115662).
Almost surely, 2121112231323 is an apocalyptic number.
121112231323 is a deficient number, since it is larger than the sum of its proper divisors (1).
121112231323 is an equidigital number, since it uses as much as digits as its factorization.
121112231323 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 432, while the sum is 22.
Adding to 121112231323 its reverse (323132211121), we get a palindrome (444244442444).
The spelling of 121112231323 in words is "one hundred twenty-one billion, one hundred twelve million, two hundred thirty-one thousand, three hundred twenty-three".
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