12111302023 has 4 divisors (see below), whose sum is σ = 12113214768. Its totient is φ = 12109389280.

The previous prime is 12111302017. The next prime is 12111302033. The reversal of 12111302023 is 32020311121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12111302023 - 2⁹ = 12111301511 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12111301988 and 12111302006.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12111302003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 946843 + ... + 959548.

It is an arithmetic number, because the mean of its divisors is an integer number (3028303692).

Almost surely, 2^12111302023 is an apocalyptic number.

12111302023 is a deficient number, since it is larger than the sum of its proper divisors (1912745).

12111302023 is an equidigital number, since it uses as much as digits as its factorization.

12111302023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1912744.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 12111302023 its reverse (32020311121), we get a palindrome (44131613144).

The spelling of 12111302023 in words is "twelve billion, one hundred eleven million, three hundred two thousand, twenty-three".