Base | Representation |
---|---|
bin | 10001100111111100111… |
… | …111001001101001101101 |
3 | 11021210010202012000212211 |
4 | 101213330333021221231 |
5 | 124320343314120323 |
6 | 2324215135530421 |
7 | 153333636016261 |
oct | 21477477115155 |
9 | 4253122160784 |
10 | 1211130223213 |
11 | 427701489579 |
12 | 176885089a11 |
13 | 8a2944a85c1 |
14 | 428948160a1 |
15 | 21786dee70d |
hex | 119fcfc9a6d |
1211130223213 has 2 divisors, whose sum is σ = 1211130223214. Its totient is φ = 1211130223212.
The previous prime is 1211130223211. The next prime is 1211130223217. The reversal of 1211130223213 is 3123220311121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1124409985924 + 86720237289 = 1060382^2 + 294483^2 .
It is a cyclic number.
It is not a de Polignac number, because 1211130223213 - 21 = 1211130223211 is a prime.
Together with 1211130223211, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211130223211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605565111606 + 605565111607.
It is an arithmetic number, because the mean of its divisors is an integer number (605565111607).
Almost surely, 21211130223213 is an apocalyptic number.
It is an amenable number.
1211130223213 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211130223213 is an equidigital number, since it uses as much as digits as its factorization.
1211130223213 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 1211130223213 its reverse (3123220311121), we get a palindrome (4334350534334).
The spelling of 1211130223213 in words is "one trillion, two hundred eleven billion, one hundred thirty million, two hundred twenty-three thousand, two hundred thirteen".
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