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121113033143 = 132817911879
BaseRepresentation
bin111000011001011100…
…1100011100110110111
3102120121120112112221012
41300302321203212313
53441014414030033
6131345532342435
711515202536664
oct1606271434667
9376546475835
10121113033143
1147400171423
121b580614a1b
13b56197c36b
145c0d0b8a6b
15323ca63248
hex1c32e639b7

121113033143 has 4 divisors (see below), whose sum is σ = 121114077840. Its totient is φ = 121111988448.

The previous prime is 121113033131. The next prime is 121113033161. The reversal of 121113033143 is 341330311121.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 121113033143 - 216 = 121112967607 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121113033163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 323123 + ... + 588756.

It is an arithmetic number, because the mean of its divisors is an integer number (30278519460).

Almost surely, 2121113033143 is an apocalyptic number.

121113033143 is a deficient number, since it is larger than the sum of its proper divisors (1044697).

121113033143 is an equidigital number, since it uses as much as digits as its factorization.

121113033143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1044696.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 121113033143 its reverse (341330311121), we get a palindrome (462443344264).

The spelling of 121113033143 in words is "one hundred twenty-one billion, one hundred thirteen million, thirty-three thousand, one hundred forty-three".

Divisors: 1 132817 911879 121113033143