12111313013 has 4 divisors (see below), whose sum is σ = 12748750560. Its totient is φ = 11473875468.

The previous prime is 12111312991. The next prime is 12111313031. The reversal of 12111313013 is 31031311121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12111313013 - 2²⁰ = 12110264437 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12111312982 and 12111313000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12111313033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 318718745 + ... + 318718782.

It is an arithmetic number, because the mean of its divisors is an integer number (3187187640).

Almost surely, 2^12111313013 is an apocalyptic number.

It is an amenable number.

12111313013 is a deficient number, since it is larger than the sum of its proper divisors (637437547).

12111313013 is an equidigital number, since it uses as much as digits as its factorization.

12111313013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 637437546.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 12111313013 its reverse (31031311121), we get a palindrome (43142624134).

The spelling of 12111313013 in words is "twelve billion, one hundred eleven million, three hundred thirteen thousand, thirteen".