12111411127 has 2 divisors, whose sum is σ = 12111411128. Its totient is φ = 12111411126.

The previous prime is 12111411101. The next prime is 12111411149. The reversal of 12111411127 is 72111411121.

It is an a-pointer prime, because the next prime (12111411149) can be obtained adding 12111411127 to its sum of digits (22).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12111411127 - 2¹⁵ = 12111378359 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12111411098 and 12111411107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12111411187) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055705563 + 6055705564.

It is an arithmetic number, because the mean of its divisors is an integer number (6055705564).

Almost surely, 2^12111411127 is an apocalyptic number.

12111411127 is a deficient number, since it is larger than the sum of its proper divisors (1).

12111411127 is an equidigital number, since it uses as much as digits as its factorization.

12111411127 is an evil number, because the sum of its binary digits is even.

The product of its digits is 112, while the sum is 22.

Adding to 12111411127 its reverse (72111411121), we get a palindrome (84222822248).

The spelling of 12111411127 in words is "twelve billion, one hundred eleven million, four hundred eleven thousand, one hundred twenty-seven".