Base | Representation |
---|---|
bin | 10001100111111101110… |
… | …000010100010110101111 |
3 | 11021210011122102212010102 |
4 | 101213331300110112233 |
5 | 124320410114041421 |
6 | 2324220320101315 |
7 | 153334153410242 |
oct | 21477560242657 |
9 | 4253148385112 |
10 | 1211143112111 |
11 | 427708792159 |
12 | 17688946483b |
13 | 8a29706c07a |
14 | 4289640d259 |
15 | 217880e860b |
hex | 119fdc145af |
1211143112111 has 2 divisors, whose sum is σ = 1211143112112. Its totient is φ = 1211143112110.
The previous prime is 1211143112093. The next prime is 1211143112159. The reversal of 1211143112111 is 1112113411121.
It is a m-pointer prime, because the next prime (1211143112159) can be obtained adding 1211143112111 to its product of digits (48).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1211143112111 - 214 = 1211143095727 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1211143112171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605571556055 + 605571556056.
It is an arithmetic number, because the mean of its divisors is an integer number (605571556056).
Almost surely, 21211143112111 is an apocalyptic number.
1211143112111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211143112111 is an equidigital number, since it uses as much as digits as its factorization.
1211143112111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 48, while the sum is 20.
Adding to 1211143112111 its reverse (1112113411121), we get a palindrome (2323256523232).
The spelling of 1211143112111 in words is "one trillion, two hundred eleven billion, one hundred forty-three million, one hundred twelve thousand, one hundred eleven".
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