Base | Representation |
---|---|
bin | 10110100011110011… |
… | …11101010011100101 |
3 | 1011021002001022012111 |
4 | 23101321331103211 |
5 | 144301030103203 |
6 | 5321452521021 |
7 | 606064420126 |
oct | 132171752345 |
9 | 34232038174 |
10 | 12111566053 |
11 | 5155732924 |
12 | 2420180171 |
13 | 11b02c7942 |
14 | 82c78004d |
15 | 4ad45c26d |
hex | 2d1e7d4e5 |
12111566053 has 2 divisors, whose sum is σ = 12111566054. Its totient is φ = 12111566052.
The previous prime is 12111566029. The next prime is 12111566069. The reversal of 12111566053 is 35066511121.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10057482369 + 2054083684 = 100287^2 + 45322^2 .
It is a cyclic number.
It is not a de Polignac number, because 12111566053 - 29 = 12111565541 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12111566023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055783026 + 6055783027.
It is an arithmetic number, because the mean of its divisors is an integer number (6055783027).
Almost surely, 212111566053 is an apocalyptic number.
It is an amenable number.
12111566053 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111566053 is an equidigital number, since it uses as much as digits as its factorization.
12111566053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 31.
The spelling of 12111566053 in words is "twelve billion, one hundred eleven million, five hundred sixty-six thousand, fifty-three".
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