121120001113 has 2 divisors, whose sum is σ = 121120001114. Its totient is φ = 121120001112.

The previous prime is 121120001077. The next prime is 121120001131. The reversal of 121120001113 is 311100021121.

It is a happy number.

Together with next prime (121120001131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 119251427584 + 1868573529 = 345328^2 + 43227^2 .

It is a cyclic number.

It is not a de Polignac number, because 121120001113 - 2¹³ = 121119992921 is a prime.

It is a super-2 number, since 2×121120001113² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 121120001093 and 121120001102.

It is not a weakly prime, because it can be changed into another prime (121120001143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60560000556 + 60560000557.

It is an arithmetic number, because the mean of its divisors is an integer number (60560000557).

Almost surely, 2^121120001113 is an apocalyptic number.

It is an amenable number.

121120001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

121120001113 is an equidigital number, since it uses as much as digits as its factorization.

121120001113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 121120001113 its reverse (311100021121), we get a palindrome (432220022234).

The spelling of 121120001113 in words is "one hundred twenty-one billion, one hundred twenty million, one thousand, one hundred thirteen".