Base | Representation |
---|---|
bin | 10110100011110111… |
… | …11111101010011101 |
3 | 1011021010001102122012 |
4 | 23101323333222131 |
5 | 144301144144442 |
6 | 5321512201005 |
7 | 606102102614 |
oct | 132173775235 |
9 | 34233042565 |
10 | 12112099997 |
11 | 5155a67aa8 |
12 | 2420399165 |
13 | 11b045399a |
14 | 82c87c87b |
15 | 4ad515582 |
hex | 2d1effa9d |
12112099997 has 2 divisors, whose sum is σ = 12112099998. Its totient is φ = 12112099996.
The previous prime is 12112099981. The next prime is 12112100023. The reversal of 12112099997 is 79999021121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12013475236 + 98624761 = 109606^2 + 9931^2 .
It is a cyclic number.
It is not a de Polignac number, because 12112099997 - 24 = 12112099981 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12112099297) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056049998 + 6056049999.
It is an arithmetic number, because the mean of its divisors is an integer number (6056049999).
Almost surely, 212112099997 is an apocalyptic number.
It is an amenable number.
12112099997 is a deficient number, since it is larger than the sum of its proper divisors (1).
12112099997 is an equidigital number, since it uses as much as digits as its factorization.
12112099997 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 183708, while the sum is 50.
The spelling of 12112099997 in words is "twelve billion, one hundred twelve million, ninety-nine thousand, nine hundred ninety-seven".
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