Base | Representation |
---|---|
bin | 1011000001000001000101… |
… | …1010110100111111110100 |
3 | 1120212220110002001011022220 |
4 | 2300100101122310333310 |
5 | 3041421040101121322 |
6 | 41432115534322340 |
7 | 2360033062322613 |
oct | 260202132647764 |
9 | 46786402034286 |
10 | 12112100020212 |
11 | 394a792777205 |
12 | 14374a59593b0 |
13 | 69b220cb38aa |
14 | 2dc32ba5587a |
15 | 1600e458655c |
hex | b04116b4ff4 |
12112100020212 has 48 divisors (see below), whose sum is σ = 28340496912000. Its totient is φ = 4026095533440.
The previous prime is 12112100020193. The next prime is 12112100020261. The reversal of 12112100020212 is 21202000121121.
It is a junction number, because it is equal to n+sod(n) for n = 12112100020191 and 12112100020200.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20949537 + ... + 21519927.
It is an arithmetic number, because the mean of its divisors is an integer number (590427019000).
Almost surely, 212112100020212 is an apocalyptic number.
12112100020212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
12112100020212 is an abundant number, since it is smaller than the sum of its proper divisors (16228396891788).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12112100020212 is a wasteful number, since it uses less digits than its factorization.
12112100020212 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 575336 (or 575334 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 15.
Adding to 12112100020212 its reverse (21202000121121), we get a palindrome (33314100141333).
The spelling of 12112100020212 in words is "twelve trillion, one hundred twelve billion, one hundred million, twenty thousand, two hundred twelve".
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