Base | Representation |
---|---|
bin | 111000011001101100… |
… | …0000001110110001011 |
3 | 102120122010120101122201 |
4 | 1300303120001312023 |
5 | 3441023440140243 |
6 | 131350415501031 |
7 | 11515330460101 |
oct | 1606330016613 |
9 | 376563511581 |
10 | 121121021323 |
11 | 47404728025 |
12 | 1b583227777 |
13 | b5635182b3 |
14 | 5c10197c71 |
15 | 323d5e004d |
hex | 1c33601d8b |
121121021323 has 2 divisors, whose sum is σ = 121121021324. Its totient is φ = 121121021322.
The previous prime is 121121021321. The next prime is 121121021339. The reversal of 121121021323 is 323120121121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121121021323 - 21 = 121121021321 is a prime.
Together with 121121021321, it forms a pair of twin primes.
It is a self number, because there is not a number n which added to its sum of digits gives 121121021323.
It is not a weakly prime, because it can be changed into another prime (121121021321) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60560510661 + 60560510662.
It is an arithmetic number, because the mean of its divisors is an integer number (60560510662).
Almost surely, 2121121021323 is an apocalyptic number.
121121021323 is a deficient number, since it is larger than the sum of its proper divisors (1).
121121021323 is an equidigital number, since it uses as much as digits as its factorization.
121121021323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 121121021323 its reverse (323120121121), we get a palindrome (444241142444).
The spelling of 121121021323 in words is "one hundred twenty-one billion, one hundred twenty-one million, twenty-one thousand, three hundred twenty-three".
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