12112111020021 has 4 divisors (see below), whose sum is σ = 16149481360032. Its totient is φ = 8074740680012.

The previous prime is 12112111020019. The next prime is 12112111020091. The reversal of 12112111020021 is 12002011121121.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12112111020021 - 2¹ = 12112111020019 is a prime.

It is a super-3 number, since 3×12112111020021³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12112111020091) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2018685170001 + ... + 2018685170006.

It is an arithmetic number, because the mean of its divisors is an integer number (4037370340008).

Almost surely, 2^{12112111020021} is an apocalyptic number.

It is an amenable number.

12112111020021 is a deficient number, since it is larger than the sum of its proper divisors (4037370340011).

12112111020021 is an equidigital number, since it uses as much as digits as its factorization.

12112111020021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4037370340010.

The product of its (nonzero) digits is 16, while the sum is 15.

Adding to 12112111020021 its reverse (12002011121121), we get a palindrome (24114122141142).

The spelling of 12112111020021 in words is "twelve trillion, one hundred twelve billion, one hundred eleven million, twenty thousand, twenty-one".