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1211211161213 is a prime number
BaseRepresentation
bin10001101000000001110…
…011111001111001111101
311021210100101111002221112
4101220001303321321331
5124321030024124323
62324231150411405
7153335641000154
oct21500163717175
94253311432845
101211211161213
11427743140489
121768a8200b65
138a2a81a6901
14428a148459b
152178e08b178
hex11a01cf9e7d

1211211161213 has 2 divisors, whose sum is σ = 1211211161214. Its totient is φ = 1211211161212.

The previous prime is 1211211161191. The next prime is 1211211161357. The reversal of 1211211161213 is 3121611121121.

It is a m-pointer prime, because the next prime (1211211161357) can be obtained adding 1211211161213 to its product of digits (144).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1026811342489 + 184399818724 = 1013317^2 + 429418^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211211161213 - 218 = 1211210899069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1211211163213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605605580606 + 605605580607.

It is an arithmetic number, because the mean of its divisors is an integer number (605605580607).

Almost surely, 21211211161213 is an apocalyptic number.

It is an amenable number.

1211211161213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211211161213 is an equidigital number, since it uses as much as digits as its factorization.

1211211161213 is an evil number, because the sum of its binary digits is even.

The product of its digits is 144, while the sum is 23.

Adding to 1211211161213 its reverse (3121611121121), we get a palindrome (4332822282334).

The spelling of 1211211161213 in words is "one trillion, two hundred eleven billion, two hundred eleven million, one hundred sixty-one thousand, two hundred thirteen".