12112120040201 has 2 divisors, whose sum is σ = 12112120040202. Its totient is φ = 12112120040200.

The previous prime is 12112120040177. The next prime is 12112120040203. The reversal of 12112120040201 is 10204002121121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9406341784576 + 2705778255625 = 3066976^2 + 1644925^2 .

It is an emirp because it is prime and its reverse (10204002121121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12112120040201 is a prime.

It is a super-2 number, since 2×12112120040201² (a number of 27 digits) contains 22 as substring.

Together with 12112120040203, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12112120040201.

It is not a weakly prime, because it can be changed into another prime (12112120040203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056060020100 + 6056060020101.

It is an arithmetic number, because the mean of its divisors is an integer number (6056060020101).

Almost surely, 2^{12112120040201} is an apocalyptic number.

It is an amenable number.

12112120040201 is a deficient number, since it is larger than the sum of its proper divisors (1).

12112120040201 is an equidigital number, since it uses as much as digits as its factorization.

12112120040201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 12112120040201 its reverse (10204002121121), we get a palindrome (22316122161322).

The spelling of 12112120040201 in words is "twelve trillion, one hundred twelve billion, one hundred twenty million, forty thousand, two hundred one".