Base | Representation |
---|---|
bin | 111000011001101100… |
… | …1001011100101000011 |
3 | 102120122011010201221012 |
4 | 1300303121023211003 |
5 | 3441024024321311 |
6 | 131350430151135 |
7 | 11515333155431 |
oct | 1606331134503 |
9 | 376564121835 |
10 | 121121323331 |
11 | 47404913a18 |
12 | 1b5833524ab |
13 | b5635c28b8 |
14 | 5c10235d51 |
15 | 323d64e78b |
hex | 1c3364b943 |
121121323331 has 2 divisors, whose sum is σ = 121121323332. Its totient is φ = 121121323330.
The previous prime is 121121323259. The next prime is 121121323333. The reversal of 121121323331 is 133323121121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121121323331 is a prime.
It is a super-2 number, since 2×1211213233312 (a number of 23 digits) contains 22 as substring.
Together with 121121323333, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 121121323297 and 121121323306.
It is not a weakly prime, because it can be changed into another prime (121121323333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60560661665 + 60560661666.
It is an arithmetic number, because the mean of its divisors is an integer number (60560661666).
Almost surely, 2121121323331 is an apocalyptic number.
121121323331 is a deficient number, since it is larger than the sum of its proper divisors (1).
121121323331 is an equidigital number, since it uses as much as digits as its factorization.
121121323331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 648, while the sum is 23.
Adding to 121121323331 its reverse (133323121121), we get a palindrome (254444444452).
The spelling of 121121323331 in words is "one hundred twenty-one billion, one hundred twenty-one million, three hundred twenty-three thousand, three hundred thirty-one".
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